An electron collides with an atom in its grou | vedclass

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(A) Let $K_i$ be the initial kinetic energy of the electron and $K_f$ be its final kinetic energy.Let $K_{atom}$ be the kinetic energy acquired by the

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Greater than $E_{photon}$

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(A) Let $K_i$ be the initial kinetic energy of the electron and $K_f$ be its final kinetic energy.Let $K_{atom}$ be the kinetic energy acquired by the atom due to the collision (recoil energy).By the law of conservation of energy: $K_i = K_f + E_{photon} + K_{atom}$.The change in the electron's energy is $\Delta E_{elec} = K_i - K_f$.Substituting this into the energy conservation equation,we get: $\Delta E_{elec} = E_{photon} + K_{atom}$.Since the atom must acquire some kinetic energy to conserve momentum during the collision,$K_{atom} > 0$.Therefore,$\Delta E_{elec} > E_{photon}$.

An electron collides with an atom in its ground state at rest. The atom then emits a photon of energy $E_{photon}$. In this process,the change $\Delta E_{elec}$ in the electron's energy is

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